What Is The First Term Of A Sequence With A Common Difference Of 7 And The 12th Term Is 64?

What is the first term of a sequence with a common difference of 7 and the 12th term is 64?

 

Answer:

The first term is -13.

Step-by-step explanation:

General rule:

an = a₁ + (n-1)(d)

Where:

an = 64

n = 12

d = 7

a₁ = unknown

Substitute:

64 = a₁ + (12-1)(7)

64 = a₁ + (11)(7)

64 = a₁ + 77

a₁= 64 - 77

a₁ = -13

The first term is -13.


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