Identify and explain some of the vital considerations needed to know on the different methods to mine a mineral deposit. Mineral Resources: Mining Methods: Answer: Vital Considerations Needed to Know on the Different Methods to Mine a Mineral Deposit: Study geological formations and then test the physical and chemical properties of soil and rocks to locate possible ore deposits. Determine the size of the deposits and the concentration of mineral ores. Decide whether a mineral deposit is worth mining. Consider the type of mining to be done. Explanation: A deposit should only be mined if it would be profitable to do so. A concentration of minerals is called an ore deposit only if it is profitable to mine. Ore deposits that are close to the surface are mined by surface mining. In doing the surface mining, any overlying rock is blasted away. The rock that contains the valuable minerals is placed in a truck and taken to a refinery. Several methods of surface mining include op...
Does anyone know how to figure this out cause I dont Please im running out of time (The bottom shape have nothing to do with the problem) Answer: B (12 sq. in) Step-by-step explanation: We are the given the ratio of two different figures: > 1 in = 5 ft > 1 in = 10 ft The given is the area of the triangle on the right is 6 sq. in. To be able to find the area of the triangle in the left. First, we need to square the ratio of the second triangle. That will become, 1 sq. in = 10 sq. ft Since we are given 6 sq. in, then we can substitute that and find how many sq. ft are there. So, 1(6) sq. in = 10(6) sq. ft which will become 6 sq. in = 60 sq. ft Next, square the equation of the first triangle which will become 1 sq. in = 5 sq. ft. Then divide the area of the second triangle by the first. That is 60 sq. ft / 5 sq. ft = 12 sq. ft Multiply it by the number of inches, 12 sq. ft x 1 sq. in = 12 sq. in Hope this helps! ~~DeanGD20
Why do we need to simplify the balanced chemical equation? Good Day... During the chemical reaction , the mass of reactant to product is not lost or not destroyed. Which means, the mass of reactant is always equal to the mass of the product. It is also understood that the number atoms of the same element is equal in both reactant and product. That is why when you balance the equation, you count the number of atoms of elements in both product and reactant making them equal. Example: Na + Cl2 → NaCl (note: only 1 chlorine atom in the product but 2 in the reactant). We balance this equation because Chlorine atoms in product should be equal to the reactant. To balance: 2 Na + Cl2 → 2 NaCl Na = 2 Na = 2 Cl = 2 Cl = 2 Hope it helps...=)
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