"A 1500 Kg Car Moving At A Velocity Of 25 Km/Hr Along Edsa Is Accelerated By A Force Of 1800 N.What Will Be Its Final Velocity After 11 Seconds? (Negl

a 1500 kg car moving at a velocity of 25 km/hr along edsa is accelerated by a force of 1800 n.What will be its final velocity after 11 seconds? (neglect friction )

 

Good Day...

Problem:

a 1500 kg car moving at a velocity of 25 km/hr along edsa is accelerated by a force of 1800 n.What will be its final velocity after 11 seconds? (neglect friction )

Given Data:

m (mass) = 1500 kg

Vi (initial velocity) = 25 km/hr

                                25 km/hr × 1000 m/ 1 km × 1hr/3600 s = 6.94 m/s

F (force) =  1800 N or 1800 kg.m/s^2

Solution:

First:

we need to find the acceleration to determine the final velocity using the formula F = mass × acceleration

To find acceleration we can use the formula a = F/m

a = F/m

  = 1800 kg.m/s^2 /1500 kg   (cancel the unit kg)

  = 1.2 m/s^2

Second:

We will solve for the final velocity using the formula a = (Vf-Vi)/t

To find Vf, we can use the formula Vf = a×t + Vi

Vf = a/t + Vi

    = 1.2 m/s^2 × 11 s + 6.94 m/s

    = 13.2 m/s + 6.94 m/s

    = 20.14 m/s

Answer:

The final velocity is 20.14 m/s

Hope it helps...=)


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